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6n^2-41n+44=0
a = 6; b = -41; c = +44;
Δ = b2-4ac
Δ = -412-4·6·44
Δ = 625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{625}=25$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-25}{2*6}=\frac{16}{12} =1+1/3 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+25}{2*6}=\frac{66}{12} =5+1/2 $
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